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{{Short description|Mathematical criterion about whether a series converges}}
{{Calculus |Series}}
{{Calculus |Series}}


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===[[Term test|Limit of the summand]]===
===[[Term test|Limit of the summand]]===
If the limit of the summand is undefined or nonzero, that is <math>\lim_{n \to \infty}a_n \ne 0</math>, then the series must diverge. In this sense, the partial sums are [[Cauchy sequence|Cauchy]] [[only if]] this limit exists and is equal to zero. The test is inconclusive if the limit of the summand is zero.
If the limit of the summand is undefined or nonzero, that is <math>\lim_{n \to \infty}a_n \ne 0</math>, then the series must diverge. In this sense, the partial sums are [[Cauchy sequence|Cauchy]] [[only if]] this limit exists and is equal to zero. The test is inconclusive if the limit of the summand is zero. This is also known as the '''nth-term test''', '''test for divergence''', or '''the divergence test'''.


===[[Ratio test]]===
===[[Ratio test]]===
This is also known as '''d'Alembert's criterion'''.
This is also known as '''d'Alembert's criterion'''.


: Consider two limits <math>\ell=\liminf_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|</math> and <math>L=\limsup_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|</math>. If <math>\ell>1</math>, the series diverges. If <math>L<1</math> then the series converges absolutely. If <math>\ell\le1\le L</math> then the test is inconclusive, and the series may converge absolutely, conditionally or diverge.
: Suppose that there exists <math>r</math> such that
:: <math>\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right| = r.</math>
: If ''r'' < 1, then the series is absolutely convergent. If ''r'' > 1, then the series diverges. If ''r'' = 1, the ratio test is inconclusive, and the series may converge or diverge.


===[[Root test]]===
===[[Root test]]===
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:: <math>r=\limsup_{n\to\infty}\sqrt[n]{|a_n|},</math>
:: <math>r=\limsup_{n\to\infty}\sqrt[n]{|a_n|},</math>
: where <math>\limsup</math> denotes the [[limit superior]] (possibly <math>\infty</math>; if the limit exists it is the same value).
: where <math>\limsup</math> denotes the [[limit superior]] (possibly <math>\infty</math>; if the limit exists it is the same value).
: If ''r'' < 1, then the series converges. If ''r'' > 1, then the series diverges. If ''r'' = 1, the root test is inconclusive, and the series may converge or diverge.
: If ''r'' < 1, then the series converges absolutely. If ''r'' > 1, then the series diverges. If ''r'' = 1, the root test is inconclusive, and the series may converge or diverge.
The root test is stronger than the ratio test: whenever the ratio test determines the convergence or divergence of an infinite series, the root test does too, but not conversely.<ref>{{cite web|url=http://www.mathcs.org/analysis/reals/numser/t_ratio.html|title=MathCS.org - Real Analysis: Ratio Test|first=Bert G.|last=Wachsmuth|website=www.mathcs.org}}</ref>
The root test is stronger than the ratio test: whenever the ratio test determines the convergence or divergence of an infinite series, the root test does too, but not conversely.<ref>{{cite web|url=http://www.mathcs.org/analysis/reals/numser/t_ratio.html|title=MathCS.org - Real Analysis: Ratio Test|first=Bert G.|last=Wachsmuth|website=www.mathcs.org}}</ref>
For example, for the series

:1 + 1 + 0.5 + 0.5 + 0.25 + 0.25 + 0.125 + 0.125 + ... = 4,

convergence follows from the root test but not from the ratio test.{{cn|date=December 2020}}


===[[Integral test]]===
===[[Integral test]]===
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In other words, the series <math>{a_n}</math> converges [[if and only if]] the integral converges.
In other words, the series <math>{a_n}</math> converges [[if and only if]] the integral converges.


====[[Harmonic series (mathematics)|p-series test]]====
===={{mvar|p}}-series test====
A commonly-used corollary of the integral test is the p-series test. Let <math>k > 0</math>. Then <math>\sum_{n=k}^{\infty} \bigg(\frac{1}{n^p}\bigg)</math> converges if <math>p > 1</math>.
A commonly-used corollary of the integral test is the p-series test. Let <math>k > 0</math>. Then <math>\sum_{n=k}^{\infty} \bigg(\frac{1}{n^p}\bigg)</math> converges if <math>p > 1</math>.


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===[[Limit comparison test]]===
===[[Limit comparison test]]===
If <math>\{a_n\},\{b_n\}>0</math>, (that is, each element of the two sequences is positive) and the limit <math>\lim_{n\to\infty} \frac{a_n}{b_n}</math> exists, is finite and non-zero, then <math>\sum_{n=1}^\infty a_n</math> diverges [[if and only if]] <math>\sum_{n=1}^\infty b_n</math> diverges.
If <math>\{a_n\},\{b_n\}>0</math>, (that is, each element of the two sequences is positive) and the limit <math>\lim_{n\to\infty} \frac{a_n}{b_n}</math> exists, is finite and non-zero, then either both series converge or both series diverge.
'''


===[[Cauchy condensation test]]===
===[[Cauchy condensation test]]===


Let <math>\left \{ a_n \right \}</math> be a positive non-increasing sequence. Then the sum <math>A = \sum_{n=1}^\infty a_n</math> converges [[if and only if]] the sum <math>A^* = \sum_{n=0}^\infty 2^n a_{2^n}</math> converges. Moreover, if they converge, then <math>A \leq A^* \leq 2A</math> holds.
Let <math>\left \{ a_n \right \}</math> be a non-negative non-increasing sequence. Then the sum <math>A = \sum_{n=1}^\infty a_n</math> converges [[if and only if]] the sum <math>A^* = \sum_{n=0}^\infty 2^n a_{2^n}</math> converges. Moreover, if they converge, then <math>A \leq A^* \leq 2A</math> holds.


===[[Abel's test]]===
===[[Abel's test]]===
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Suppose the following statements are true:
Suppose the following statements are true:


* <math> \lim_{n \to \infty} a_n = 0 </math> and
* <math> (a_n)_{n=1}^\infty </math> is monotonic,
* for every ''n'', <math> a_{n+1} \le a_n </math>.
* <math> \lim_{n \to \infty} a_n = 0 </math>
Then <math> \sum_{n = 1}^\infty (-1)^{n} a_n </math> and <math> \sum_{n = 1}^\infty (-1)^{n+1} a_n </math> are convergent series.

Then <math> \sum_{n = k}^\infty (-1)^{n} a_n </math> and <math> \sum_{n = k}^\infty (-1)^{n+1} a_n </math> are convergent series.
This test is also known as the '''Leibniz criterion'''.
This test is also known as the '''Leibniz criterion'''.


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converges.
converges.


===[[Ratio test#2. Raabe's test|Raabe–Duhamel's test]]===
===[[Cauchy's convergence test]]===


A series <math>\sum_{i=0}^\infty a_i</math> is convergent if and only if for every <math>\varepsilon>0</math> there is a natural number ''N'' such that
Let <math>a_n>0</math>.

:<math>|a_{n+1}+a_{n+2}+\cdots+a_{n+p}|<\varepsilon</math>

holds for all {{nobreak|''n'' > ''N''}} and all {{nobreak|''p'' ≥ 1}}.

===[[Stolz–Cesàro theorem]]===

Let <math>(a_n)_{n \geq 1}</math> and <math>(b_n)_{n \geq 1}</math> be two sequences of real numbers. Assume that <math>(b_n)_{n \geq 1}</math> is a [[Monotonic function|strictly monotone]] and divergent sequence and the following limit exists:
:<math> \lim_{n \to \infty} \frac{a_{n+1}-a_n}{b_{n+1}-b_n}=l.\ </math>
Then, the limit
:<math> \lim_{n \to \infty} \frac{a_n}{b_n}=l.\ </math>

===[[Weierstrass M-test]]===

Suppose that (''f''<sub>''n''</sub>) is a sequence of real- or complex-valued functions defined on a set ''A'', and that there is a sequence of non-negative numbers (''M''<sub>''n''</sub>) satisfying the conditions
* <math>|f_n(x)|\leq M_n</math> for all <math>n \geq 1</math> and all <math>x \in A</math>, and
* <math>\sum_{n=1}^{\infty} M_n </math> converges.
Then the series
:<math>\sum_{n=1}^{\infty} f_n (x)</math>
converges absolutely and [[uniform convergence|uniformly]] on ''A''.

===Extensions to the ratio test===

The ratio test may be inconclusive when the limit of the ratio is 1. Extensions to the ratio test, however, sometimes allows one to deal with this case.

====[[Ratio test#2. Raabe's test|Raabe–Duhamel's test]]====

Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers.


Define
Define
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exists there are three possibilities:
exists there are three possibilities:


* if ''L'' > 1 the series converges
* if ''L'' > 1 the series converges (this includes the case ''L'' = ∞)
* if ''L'' < 1 the series diverges
* if ''L'' < 1 the series diverges
* and if ''L'' = 1 the test is inconclusive.
* and if ''L'' = 1 the test is inconclusive.
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for all ''n'' > ''K'' then the series {''a''<sub>''n''</sub>} is convergent.
for all ''n'' > ''K'' then the series {''a''<sub>''n''</sub>} is convergent.


===[[Ratio test#3. Bertrand’s test|Bertrand's test]]===
====[[Ratio test#3. Bertrand's test|Bertrand's test]]====


Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers.
Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers.
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exists, there are three possibilities:<ref>František Ďuriš, ''[http://oldwww.dcs.fmph.uniba.sk/bakalarky/obhajene/getfile.php/new.pdf?id=90&fid=228&type=application%2Fpdf Infinite series: Convergence tests]'', pp. 24–9. Bachelor's thesis.</ref><ref>{{Cite web|url=https://mathworld.wolfram.com/BertrandsTest.html|title=Bertrand's Test|last=Weisstein|first=Eric W.|website=mathworld.wolfram.com|language=en|access-date=2020-04-16}}</ref>
exists, there are three possibilities:<ref>František Ďuriš, ''[http://oldwww.dcs.fmph.uniba.sk/bakalarky/obhajene/getfile.php/new.pdf?id=90&fid=228&type=application%2Fpdf Infinite series: Convergence tests]'', pp. 24–9. Bachelor's thesis.</ref><ref>{{Cite web|url=https://mathworld.wolfram.com/BertrandsTest.html|title=Bertrand's Test|last=Weisstein|first=Eric W.|website=mathworld.wolfram.com|language=en|access-date=2020-04-16}}</ref>


* if ''L'' > 1 the series converges
* if ''L'' > 1 the series converges (this includes the case ''L'' = ∞)
* if ''L'' < 1 the series diverges
* if ''L'' < 1 the series diverges
* and if ''L'' = 1 the test is inconclusive.
* and if ''L'' = 1 the test is inconclusive.


===[[Ratio test#5. Gauss’s test|Gauss's test]]===
====[[Ratio test#5. Gauss's test|Gauss's test]]====
Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers. If <math>\frac{a_n}{a_{n + 1}} = 1+ \frac{\alpha}{n} + O(1/n^\beta)</math> for some β > 1, then <math> \sum a_n</math> converges if {{math|α > 1}} and diverges if {{math|α ≤ 1}}.<ref>* {{SpringerEOM |id=Gauss_criterion&oldid=39905 |title=Gauss criterion}}</ref>
Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers. If <math>\frac{a_n}{a_{n + 1}} = 1+ \frac{\alpha}{n} + O(1/n^\beta)</math> for some β > 1, then <math> \sum a_n</math> converges if {{math|α > 1}} and diverges if {{math|α ≤ 1}}.<ref>* {{SpringerEOM |id=Gauss_criterion&oldid=39905 |title=Gauss criterion}}</ref>

====[[Ratio test#6. Kummer's test|Kummer's test]]====
Let { ''a''<sub>''n''</sub> } be a sequence of positive numbers. Then:<ref>{{Cite journal|date=1835-01-01|title=Über die Convergenz und Divergenz der unendlichen Reihen.|url=https://www.degruyter.com/document/doi/10.1515/crll.1835.13.171/html|journal=Journal für die reine und angewandte Mathematik|volume=1835|issue=13|pages=171–184|doi=10.1515/crll.1835.13.171|s2cid=121050774|issn=0075-4102}}</ref><ref>{{Cite journal|last=Tong|first=Jingcheng|date=1994|title=Kummer's Test Gives Characterizations for Convergence or Divergence of all Positive Series|url=https://www.jstor.org/stable/2974907|journal=The American Mathematical Monthly|volume=101|issue=5|pages=450–452|doi=10.2307/2974907|jstor=2974907}}</ref><ref>{{Cite journal|last=Samelson|first=Hans|date=1995|title=More on Kummer's Test|url=https://www.tandfonline.com/doi/full/10.1080/00029890.1995.12004667|journal=The American Mathematical Monthly|language=en|volume=102|issue=9|pages=817–818|doi=10.1080/00029890.1995.12004667|issn=0002-9890}}</ref>

(1) <math> \sum a_n</math> converges if and only if there is a sequence <math>b_{n}</math> of positive numbers and a real number ''c'' > 0 such that <math>b_k (a_{k}/a_{k+1}) - b_{k+1} \ge c</math>.

(2) <math> \sum a_n</math> diverges if and only if there is a sequence <math>b_{n}</math> of positive numbers such that <math>b_k (a_{k}/a_{k+1}) - b_{k+1} \le 0</math>

and <math> \sum 1/b_{n}</math> diverges.

===Abu-Mostafa's test===
Let <math>\sum_{n=1}^\infty a_n</math> be an infinite series with real terms and let <math>f:\R\to\R</math> be any real function such that <math>f(1/n)=a_n</math> for all positive integers ''n'' and the second derivative <math>f''</math> exists at <math>x=0</math>. Then <math>\sum_{n=1}^\infty a_n</math> converges absolutely if <math>f(0)=f'(0)=0</math> and diverges otherwise.<ref>{{Cite journal|last=Abu-Mostafa|first=Yaser|date=1984|title=A Differentiation Test for Absolute Convergence|url=https://work.caltech.edu/paper/Abu-Mostafa17280.pdf|journal=Mathematics Magazine|volume=57|issue=4|pages=228–231}}</ref>


===Notes===
===Notes===
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Consider the series
Consider the series


<math>(*) \;\;\; \sum_{n=1}^{\infty} \frac{1}{n^\alpha}.</math>
{{NumBlk|:|<math>\sum_{n=1}^{\infty} \frac{1}{n^\alpha}.</math>|{{EquationRef|i}}}}


[[Cauchy condensation test]] implies that (*) is finitely convergent if
[[Cauchy condensation test]] implies that ({{EquationNote|i}}) is finitely convergent if


: <math> (**) \;\;\; \sum_{n=1}^\infty 2^n \left( \frac 1 {2^n}\right)^\alpha </math>
{{NumBlk|:|<math> \sum_{n=1}^\infty 2^n \left( \frac 1 {2^n}\right)^\alpha </math>|{{EquationRef|ii}}}}


is finitely convergent. Since
is finitely convergent. Since
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: <math>\sum_{n=1}^\infty 2^n \left( \frac 1 {2^n} \right)^\alpha = \sum_{n=1}^\infty 2^{n-n\alpha} = \sum_{n=1}^\infty 2^{(1-\alpha) n} </math>
: <math>\sum_{n=1}^\infty 2^n \left( \frac 1 {2^n} \right)^\alpha = \sum_{n=1}^\infty 2^{n-n\alpha} = \sum_{n=1}^\infty 2^{(1-\alpha) n} </math>


(**) is geometric series with ratio <math> 2^{(1-\alpha)} </math>. (**) is finitely convergent if its ratio is less than one (namely <math>\alpha > 1</math>). Thus, (*) is finitely convergent [[if and only if]] <math> \alpha > 1 </math>.
({{EquationNote|ii}}) is a geometric series with ratio <math> 2^{(1-\alpha)} </math>. ({{EquationNote|ii}}) is finitely convergent if its ratio is less than one (namely {{nowrap|<math>\alpha > 1</math>).}} Thus, ({{EquationNote|i}}) is finitely convergent [[if and only if]] {{nowrap|<math>\alpha > 1</math>.}}


== Convergence of products ==
== Convergence of products ==
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== Further reading ==
== Further reading ==
* {{cite book |first=Louis |last=Leithold |author-link=Louis Leithold |title=The Calculus, with Analytic Geometry |location=New York |publisher=Harper & Row |edition=2nd |year=1972 |isbn=0-06-043959-9 |pages=655–737 }}
* {{cite book |first=Louis |last=Leithold |author-link=Louis Leithold |title=The Calculus, with Analytic Geometry |location=New York |publisher=Harper & Row |edition=2nd |year=1972 |isbn=0-06-043959-9 |pages=655–737 }}

== External links ==
* [http://www.math.tamu.edu/~austin/serieschart.pdf Flowchart for choosing convergence test]


[[Category:Convergence tests| ]]
[[Category:Convergence tests| ]]

Latest revision as of 11:15, 25 September 2024

In mathematics, convergence tests are methods of testing for the convergence, conditional convergence, absolute convergence, interval of convergence or divergence of an infinite series .

List of tests

[edit]

If the limit of the summand is undefined or nonzero, that is , then the series must diverge. In this sense, the partial sums are Cauchy only if this limit exists and is equal to zero. The test is inconclusive if the limit of the summand is zero. This is also known as the nth-term test, test for divergence, or the divergence test.

This is also known as d'Alembert's criterion.

Consider two limits and . If , the series diverges. If then the series converges absolutely. If then the test is inconclusive, and the series may converge absolutely, conditionally or diverge.

This is also known as the nth root test or Cauchy's criterion.

Let
where denotes the limit superior (possibly ; if the limit exists it is the same value).
If r < 1, then the series converges absolutely. If r > 1, then the series diverges. If r = 1, the root test is inconclusive, and the series may converge or diverge.

The root test is stronger than the ratio test: whenever the ratio test determines the convergence or divergence of an infinite series, the root test does too, but not conversely.[1]

The series can be compared to an integral to establish convergence or divergence. Let be a non-negative and monotonically decreasing function such that . If then the series converges. But if the integral diverges, then the series does so as well. In other words, the series converges if and only if the integral converges.

p-series test

[edit]

A commonly-used corollary of the integral test is the p-series test. Let . Then converges if .

The case of yields the harmonic series, which diverges. The case of is the Basel problem and the series converges to . In general, for , the series is equal to the Riemann zeta function applied to , that is .

If the series is an absolutely convergent series and for sufficiently large n , then the series converges absolutely.

If , (that is, each element of the two sequences is positive) and the limit exists, is finite and non-zero, then either both series converge or both series diverge.

Let be a non-negative non-increasing sequence. Then the sum converges if and only if the sum converges. Moreover, if they converge, then holds.

Suppose the following statements are true:

  1. is a convergent series,
  2. is a monotonic sequence, and
  3. is bounded.

Then is also convergent.

Every absolutely convergent series converges.

Suppose the following statements are true:

  • is monotonic,

Then and are convergent series. This test is also known as the Leibniz criterion.

If is a sequence of real numbers and a sequence of complex numbers satisfying

  • for every positive integer N

where M is some constant, then the series

converges.

A series is convergent if and only if for every there is a natural number N such that

holds for all n > N and all p ≥ 1.

Let and be two sequences of real numbers. Assume that is a strictly monotone and divergent sequence and the following limit exists:

Then, the limit

Suppose that (fn) is a sequence of real- or complex-valued functions defined on a set A, and that there is a sequence of non-negative numbers (Mn) satisfying the conditions

  • for all and all , and
  • converges.

Then the series

converges absolutely and uniformly on A.

Extensions to the ratio test

[edit]

The ratio test may be inconclusive when the limit of the ratio is 1. Extensions to the ratio test, however, sometimes allows one to deal with this case.

Let { an } be a sequence of positive numbers.

Define

If

exists there are three possibilities:

  • if L > 1 the series converges (this includes the case L = ∞)
  • if L < 1 the series diverges
  • and if L = 1 the test is inconclusive.

An alternative formulation of this test is as follows. Let { an } be a series of real numbers. Then if b > 1 and K (a natural number) exist such that

for all n > K then the series {an} is convergent.

Let { an } be a sequence of positive numbers.

Define

If

exists, there are three possibilities:[2][3]

  • if L > 1 the series converges (this includes the case L = ∞)
  • if L < 1 the series diverges
  • and if L = 1 the test is inconclusive.

Let { an } be a sequence of positive numbers. If for some β > 1, then converges if α > 1 and diverges if α ≤ 1.[4]

Let { an } be a sequence of positive numbers. Then:[5][6][7]

(1) converges if and only if there is a sequence of positive numbers and a real number c > 0 such that .

(2) diverges if and only if there is a sequence of positive numbers such that

and diverges.

Abu-Mostafa's test

[edit]

Let be an infinite series with real terms and let be any real function such that for all positive integers n and the second derivative exists at . Then converges absolutely if and diverges otherwise.[8]

Notes

[edit]
  • For some specific types of series there are more specialized convergence tests, for instance for Fourier series there is the Dini test.

Examples

[edit]

Consider the series

(i)

Cauchy condensation test implies that (i) is finitely convergent if

(ii)

is finitely convergent. Since

(ii) is a geometric series with ratio . (ii) is finitely convergent if its ratio is less than one (namely ). Thus, (i) is finitely convergent if and only if .

Convergence of products

[edit]

While most of the tests deal with the convergence of infinite series, they can also be used to show the convergence or divergence of infinite products. This can be achieved using following theorem: Let be a sequence of positive numbers. Then the infinite product converges if and only if the series converges. Also similarly, if holds, then approaches a non-zero limit if and only if the series converges .

This can be proved by taking the logarithm of the product and using limit comparison test.[9]

See also

[edit]

References

[edit]
  1. ^ Wachsmuth, Bert G. "MathCS.org - Real Analysis: Ratio Test". www.mathcs.org.
  2. ^ František Ďuriš, Infinite series: Convergence tests, pp. 24–9. Bachelor's thesis.
  3. ^ Weisstein, Eric W. "Bertrand's Test". mathworld.wolfram.com. Retrieved 2020-04-16.
  4. ^ * "Gauss criterion", Encyclopedia of Mathematics, EMS Press, 2001 [1994]
  5. ^ "Über die Convergenz und Divergenz der unendlichen Reihen". Journal für die reine und angewandte Mathematik. 1835 (13): 171–184. 1835-01-01. doi:10.1515/crll.1835.13.171. ISSN 0075-4102. S2CID 121050774.
  6. ^ Tong, Jingcheng (1994). "Kummer's Test Gives Characterizations for Convergence or Divergence of all Positive Series". The American Mathematical Monthly. 101 (5): 450–452. doi:10.2307/2974907. JSTOR 2974907.
  7. ^ Samelson, Hans (1995). "More on Kummer's Test". The American Mathematical Monthly. 102 (9): 817–818. doi:10.1080/00029890.1995.12004667. ISSN 0002-9890.
  8. ^ Abu-Mostafa, Yaser (1984). "A Differentiation Test for Absolute Convergence" (PDF). Mathematics Magazine. 57 (4): 228–231.
  9. ^ Belk, Jim (26 January 2008). "Convergence of Infinite Products".

Further reading

[edit]