1899 Queensland colonial election
Appearance
(Redirected from Queensland state election, 1899)
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All 72 seats in the Legislative Assembly of Queensland 37 Assembly seats were needed for a majority | |||||||||||||||||||||||||
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Elections were held in the Colony of Queensland between 1 March 1899 and 25 March 1899 to elect the members of the colony’s Legislative Assembly.
Key dates
[edit]Due to problems of distance and communications, it was not possible to hold the elections on a single day.[1]
Results
[edit]
Queensland colonial election, 11 March 1899[2] | ||||||
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Enrolled voters | 97,046 | |||||
Votes cast | 74,919 | Turnout | 79.13% | |||
Informal votes | 879 | Informal | ||||
Summary of votes by party | ||||||
Party | Primary votes | % | Swing | Seats | Change | |
Ministerialist | 46,953 | 49.34 | +1.52 | 43 | +2 | |
Labour | 33,756 | 35.47 | +0.51 | 21 | +1 | |
Opposition | 10,548 | 11.09 | +0.72 | 8 | ±0 | |
Independent | 3,898 | 4.10 | -0.32 | 0 | -2 | |
Total | 95,155 | 72 |
See also
[edit]References
[edit]- ^ "Queensland General Election Dates 1860-1929" (PDF). Queensland Parliament. Archived from the original (PDF) on 16 December 2013. Retrieved 16 December 2013.
- ^ "Summary of 1899 Election". University of Western Australia. Retrieved 26 July 2017.