1892 Rhode Island gubernatorial election
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The 1892 Rhode Island gubernatorial election was held on April 6, 1892. Republican nominee Daniel Russell Brown defeated Democratic nominee William T. C. Wardwell with 50.22% of the vote.
General election
[edit]Candidates
[edit]Major party candidates
- Daniel Russell Brown, Republican
- William T. C. Wardwell, Democratic
Other candidates
- Alexander Gilbert, Prohibition
- Franklin E. Burton, People's
Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Daniel Russell Brown | 27,461 | 50.22% | ||
| Democratic | William T. C. Wardwell | 25,433 | 46.51% | ||
| Prohibition | Alexander Gilbert | 1,598 | 2.92% | ||
| Populist | Franklin E. Burton | 187 | 0.34% | ||
| Majority | 2,028 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
[edit]- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 24, 2020.
