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1989 Virginia Slims of Los Angeles

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1989 Virginia Slims of Los Angeles
DateAugust 7–13
Edition16th
Category5
Draw56S / 28D
Prize money$300,000
SurfaceHard / outdoor
LocationManhattan Beach, CA, U.S.
VenueManhattan Country Club
Champions
Singles
United States Martina Navratilova
Doubles
United States Martina Navratilova
Australia Wendy Turnbull
← 1988 · Virginia Slims of Los Angeles · 1990 →

The 1989 Virginia Slims of Los Angeles was a women's tennis tournament played on outdoor hard courts at the Manhattan Country Club in Manhattan Beach, California in the United States that was part of the Category 5 tier of the 1989 WTA Tour. It was the 16th edition of the tournament and was held from August 7 through August 13, 1989. First-seeded Martina Navratilova won the singles title, her sixth at the event.[1][2]

Finals

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Singles

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United States Martina Navratilova defeated Argentina Gabriela Sabatini 6–0, 6–2

  • It was Navratilova's 5th singles title of the year and the 143rd of her career.

Doubles

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United States Martina Navratilova / Australia Wendy Turnbull defeated United States Mary Joe Fernández / West Germany Claudia Kohde-Kilsch 5–2 (Fernández and Kohde-Kilsch retired)

  • It was Navratilova's 9th title of the year and the 290th of her career. It was Turnbull's only title of the year and the 58th of her career.

References

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  1. ^ Bloch Shallouf, Renee; Reynolds, Robyn, eds. (1990). 1990 Women's International Tennis Association Media Guide. Miami: WITA.
  2. ^ John Barrett, ed. (1990). The International Tennis Federation : World of Tennis 1990. London: Willow Books. pp. 165, 191–192. ISBN 9780002183550.
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