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1819 Rhode Island gubernatorial election

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1819 Rhode Island gubernatorial election

← 1818 April 21, 1819[1] 1820 →
 
Nominee Nehemiah Rice Knight
Party Democratic-Republican
Popular vote 2,664
Percentage 100%

County results
Knight:      90–100%

Governor before election

Nehemiah Rice Knight
Democratic-Republican

Elected Governor

Nehemiah Rice Knight
Democratic-Republican

The 1819 Rhode Island gubernatorial election was an uncontested election held on April 21, 1819 to elect the governor of Rhode Island. Nehemiah Rice Knight, the incumbent governor and Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.

General election

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Candidates

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  • Nehemiah Rice Knight, the incumbent governor since 1817.[2]

Results

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1819 Rhode Island gubernatorial election[3][4]
Party Candidate Votes % ±%
Democratic-Republican Nehemiah Rice Knight (incumbent) 2,670 100%
Majority 2,670 100%
Democratic-Republican hold Swing

County results

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County results
County[3] Nehemiah Knight

Democratic-Republican

Total votes
# %
Bristol 175 100% 175
Kent 473 100% 473
Newport 518 100% 518
Providence 1,056 100% 1,056
Washington 448 100% 448
Totals 2,670 100% 2,670

References

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  1. ^ "Election". The Rhode-Island Republican. Newport, R.I. April 21, 1819. p. 2. Retrieved October 24, 2021.
  2. ^ "KNIGHT, Nehemiah Rice". Biographical Directory of the United States Congress. Retrieved June 2, 2022.
  3. ^ a b "Rhode Island 1819 Governor". A New Nation Votes: American Election Returns 1787-1825. January 11, 2012. Retrieved June 2, 2022.
  4. ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 232. ISBN 9780786414390.